UBIFS: push empty flash hack down
We have a hack which forces the amount of flash space to be
equivalent to 'c->blocks_cnt' in case of empty FS. This is
to make users happy and see '%0' used in 'df' when they
mount an empty FS. This hack is not needed in
'ubifs_calc_available()', but it is only needed the caller,
in 'ubifs_budg_get_free_space()'. So push it down there.
Signed-off-by: Artem Bityutskiy <Artem.Bityutskiy@nokia.com>
diff --git a/fs/ubifs/budget.c b/fs/ubifs/budget.c
index ac0d2e1..f6d2eaa 100644
--- a/fs/ubifs/budget.c
+++ b/fs/ubifs/budget.c
@@ -302,18 +302,6 @@
int subtract_lebs;
long long available;
- /*
- * Force the amount available to the total size reported if the used
- * space is zero.
- */
- if (c->lst.total_used <= UBIFS_INO_NODE_SZ &&
- c->budg_data_growth + c->budg_dd_growth == 0) {
- /* Do the same calculation as for c->block_cnt */
- available = c->main_lebs - 2;
- available *= c->leb_size - c->dark_wm;
- return available;
- }
-
available = c->main_bytes - c->lst.total_used;
/*
@@ -739,8 +727,18 @@
return 0;
}
- available = ubifs_calc_available(c, min_idx_lebs);
outstanding = c->budg_data_growth + c->budg_dd_growth;
+
+ /*
+ * Force the amount available to the total size reported if the used
+ * space is zero.
+ */
+ if (c->lst.total_used <= UBIFS_INO_NODE_SZ && !outstanding) {
+ spin_unlock(&c->space_lock);
+ return (long long)c->block_cnt << UBIFS_BLOCK_SHIFT;
+ }
+
+ available = ubifs_calc_available(c, min_idx_lebs);
spin_unlock(&c->space_lock);
if (available > outstanding)