| Linus Torvalds | 1da177e | 2005-04-16 15:20:36 -0700 | [diff] [blame] | 1 | | | 
|  | 2 | |	binstr.sa 3.3 12/19/90 | 
|  | 3 | | | 
|  | 4 | | | 
|  | 5 | |	Description: Converts a 64-bit binary integer to bcd. | 
|  | 6 | | | 
|  | 7 | |	Input: 64-bit binary integer in d2:d3, desired length (LEN) in | 
|  | 8 | |          d0, and a  pointer to start in memory for bcd characters | 
|  | 9 | |          in d0. (This pointer must point to byte 4 of the first | 
|  | 10 | |          lword of the packed decimal memory string.) | 
|  | 11 | | | 
|  | 12 | |	Output:	LEN bcd digits representing the 64-bit integer. | 
|  | 13 | | | 
|  | 14 | |	Algorithm: | 
|  | 15 | |		The 64-bit binary is assumed to have a decimal point before | 
|  | 16 | |		bit 63.  The fraction is multiplied by 10 using a mul by 2 | 
|  | 17 | |		shift and a mul by 8 shift.  The bits shifted out of the | 
|  | 18 | |		msb form a decimal digit.  This process is iterated until | 
|  | 19 | |		LEN digits are formed. | 
|  | 20 | | | 
|  | 21 | |	A1. Init d7 to 1.  D7 is the byte digit counter, and if 1, the | 
|  | 22 | |		digit formed will be assumed the least significant.  This is | 
|  | 23 | |		to force the first byte formed to have a 0 in the upper 4 bits. | 
|  | 24 | | | 
|  | 25 | |	A2. Beginning of the loop: | 
|  | 26 | |		Copy the fraction in d2:d3 to d4:d5. | 
|  | 27 | | | 
|  | 28 | |	A3. Multiply the fraction in d2:d3 by 8 using bit-field | 
|  | 29 | |		extracts and shifts.  The three msbs from d2 will go into | 
|  | 30 | |		d1. | 
|  | 31 | | | 
|  | 32 | |	A4. Multiply the fraction in d4:d5 by 2 using shifts.  The msb | 
|  | 33 | |		will be collected by the carry. | 
|  | 34 | | | 
|  | 35 | |	A5. Add using the carry the 64-bit quantities in d2:d3 and d4:d5 | 
|  | 36 | |		into d2:d3.  D1 will contain the bcd digit formed. | 
|  | 37 | | | 
|  | 38 | |	A6. Test d7.  If zero, the digit formed is the ms digit.  If non- | 
|  | 39 | |		zero, it is the ls digit.  Put the digit in its place in the | 
|  | 40 | |		upper word of d0.  If it is the ls digit, write the word | 
|  | 41 | |		from d0 to memory. | 
|  | 42 | | | 
|  | 43 | |	A7. Decrement d6 (LEN counter) and repeat the loop until zero. | 
|  | 44 | | | 
|  | 45 | |	Implementation Notes: | 
|  | 46 | | | 
|  | 47 | |	The registers are used as follows: | 
|  | 48 | | | 
|  | 49 | |		d0: LEN counter | 
|  | 50 | |		d1: temp used to form the digit | 
|  | 51 | |		d2: upper 32-bits of fraction for mul by 8 | 
|  | 52 | |		d3: lower 32-bits of fraction for mul by 8 | 
|  | 53 | |		d4: upper 32-bits of fraction for mul by 2 | 
|  | 54 | |		d5: lower 32-bits of fraction for mul by 2 | 
|  | 55 | |		d6: temp for bit-field extracts | 
|  | 56 | |		d7: byte digit formation word;digit count {0,1} | 
|  | 57 | |		a0: pointer into memory for packed bcd string formation | 
|  | 58 | | | 
|  | 59 |  | 
|  | 60 | |		Copyright (C) Motorola, Inc. 1990 | 
|  | 61 | |			All Rights Reserved | 
|  | 62 | | | 
| Matt Waddel | e00d82d | 2006-02-11 17:55:48 -0800 | [diff] [blame] | 63 | |       For details on the license for this file, please see the | 
|  | 64 | |       file, README, in this same directory. | 
| Linus Torvalds | 1da177e | 2005-04-16 15:20:36 -0700 | [diff] [blame] | 65 |  | 
|  | 66 | |BINSTR    idnt    2,1 | Motorola 040 Floating Point Software Package | 
|  | 67 |  | 
|  | 68 | |section	8 | 
|  | 69 |  | 
|  | 70 | #include "fpsp.h" | 
|  | 71 |  | 
|  | 72 | .global	binstr | 
|  | 73 | binstr: | 
|  | 74 | moveml	%d0-%d7,-(%a7) | 
|  | 75 | | | 
|  | 76 | | A1: Init d7 | 
|  | 77 | | | 
|  | 78 | moveql	#1,%d7			|init d7 for second digit | 
|  | 79 | subql	#1,%d0			|for dbf d0 would have LEN+1 passes | 
|  | 80 | | | 
|  | 81 | | A2. Copy d2:d3 to d4:d5.  Start loop. | 
|  | 82 | | | 
|  | 83 | loop: | 
|  | 84 | movel	%d2,%d4			|copy the fraction before muls | 
|  | 85 | movel	%d3,%d5			|to d4:d5 | 
|  | 86 | | | 
|  | 87 | | A3. Multiply d2:d3 by 8; extract msbs into d1. | 
|  | 88 | | | 
|  | 89 | bfextu	%d2{#0:#3},%d1		|copy 3 msbs of d2 into d1 | 
|  | 90 | asll	#3,%d2			|shift d2 left by 3 places | 
|  | 91 | bfextu	%d3{#0:#3},%d6		|copy 3 msbs of d3 into d6 | 
|  | 92 | asll	#3,%d3			|shift d3 left by 3 places | 
|  | 93 | orl	%d6,%d2			|or in msbs from d3 into d2 | 
|  | 94 | | | 
|  | 95 | | A4. Multiply d4:d5 by 2; add carry out to d1. | 
|  | 96 | | | 
|  | 97 | asll	#1,%d5			|mul d5 by 2 | 
|  | 98 | roxll	#1,%d4			|mul d4 by 2 | 
|  | 99 | swap	%d6			|put 0 in d6 lower word | 
|  | 100 | addxw	%d6,%d1			|add in extend from mul by 2 | 
|  | 101 | | | 
|  | 102 | | A5. Add mul by 8 to mul by 2.  D1 contains the digit formed. | 
|  | 103 | | | 
|  | 104 | addl	%d5,%d3			|add lower 32 bits | 
|  | 105 | nop				|ERRATA ; FIX #13 (Rev. 1.2 6/6/90) | 
|  | 106 | addxl	%d4,%d2			|add with extend upper 32 bits | 
|  | 107 | nop				|ERRATA ; FIX #13 (Rev. 1.2 6/6/90) | 
|  | 108 | addxw	%d6,%d1			|add in extend from add to d1 | 
|  | 109 | swap	%d6			|with d6 = 0; put 0 in upper word | 
|  | 110 | | | 
|  | 111 | | A6. Test d7 and branch. | 
|  | 112 | | | 
|  | 113 | tstw	%d7			|if zero, store digit & to loop | 
|  | 114 | beqs	first_d			|if non-zero, form byte & write | 
|  | 115 | sec_d: | 
|  | 116 | swap	%d7			|bring first digit to word d7b | 
|  | 117 | aslw	#4,%d7			|first digit in upper 4 bits d7b | 
|  | 118 | addw	%d1,%d7			|add in ls digit to d7b | 
|  | 119 | moveb	%d7,(%a0)+		|store d7b byte in memory | 
|  | 120 | swap	%d7			|put LEN counter in word d7a | 
|  | 121 | clrw	%d7			|set d7a to signal no digits done | 
|  | 122 | dbf	%d0,loop		|do loop some more! | 
|  | 123 | bras	end_bstr		|finished, so exit | 
|  | 124 | first_d: | 
|  | 125 | swap	%d7			|put digit word in d7b | 
|  | 126 | movew	%d1,%d7			|put new digit in d7b | 
|  | 127 | swap	%d7			|put LEN counter in word d7a | 
|  | 128 | addqw	#1,%d7			|set d7a to signal first digit done | 
|  | 129 | dbf	%d0,loop		|do loop some more! | 
|  | 130 | swap	%d7			|put last digit in string | 
|  | 131 | lslw	#4,%d7			|move it to upper 4 bits | 
|  | 132 | moveb	%d7,(%a0)+		|store it in memory string | 
|  | 133 | | | 
|  | 134 | | Clean up and return with result in fp0. | 
|  | 135 | | | 
|  | 136 | end_bstr: | 
|  | 137 | moveml	(%a7)+,%d0-%d7 | 
|  | 138 | rts | 
|  | 139 | |end |