Linux-2.6.12-rc2

Initial git repository build. I'm not bothering with the full history,
even though we have it. We can create a separate "historical" git
archive of that later if we want to, and in the meantime it's about
3.2GB when imported into git - space that would just make the early
git days unnecessarily complicated, when we don't have a lot of good
infrastructure for it.

Let it rip!
diff --git a/arch/i386/math-emu/div_Xsig.S b/arch/i386/math-emu/div_Xsig.S
new file mode 100644
index 0000000..f77ba30
--- /dev/null
+++ b/arch/i386/math-emu/div_Xsig.S
@@ -0,0 +1,365 @@
+	.file	"div_Xsig.S"
+/*---------------------------------------------------------------------------+
+ |  div_Xsig.S                                                               |
+ |                                                                           |
+ | Division subroutine for 96 bit quantities                                 |
+ |                                                                           |
+ | Copyright (C) 1994,1995                                                   |
+ |                       W. Metzenthen, 22 Parker St, Ormond, Vic 3163,      |
+ |                       Australia.  E-mail billm@jacobi.maths.monash.edu.au |
+ |                                                                           |
+ |                                                                           |
+ +---------------------------------------------------------------------------*/
+
+/*---------------------------------------------------------------------------+
+ | Divide the 96 bit quantity pointed to by a, by that pointed to by b, and  |
+ | put the 96 bit result at the location d.                                  |
+ |                                                                           |
+ | The result may not be accurate to 96 bits. It is intended for use where   |
+ | a result better than 64 bits is required. The result should usually be    |
+ | good to at least 94 bits.                                                 |
+ | The returned result is actually divided by one half. This is done to      |
+ | prevent overflow.                                                         |
+ |                                                                           |
+ |  .aaaaaaaaaaaaaa / .bbbbbbbbbbbbb  ->  .dddddddddddd                      |
+ |                                                                           |
+ |  void div_Xsig(Xsig *a, Xsig *b, Xsig *dest)                              |
+ |                                                                           |
+ +---------------------------------------------------------------------------*/
+
+#include "exception.h"
+#include "fpu_emu.h"
+
+
+#define	XsigLL(x)	(x)
+#define	XsigL(x)	4(x)
+#define	XsigH(x)	8(x)
+
+
+#ifndef NON_REENTRANT_FPU
+/*
+	Local storage on the stack:
+	Accumulator:	FPU_accum_3:FPU_accum_2:FPU_accum_1:FPU_accum_0
+ */
+#define FPU_accum_3	-4(%ebp)
+#define FPU_accum_2	-8(%ebp)
+#define FPU_accum_1	-12(%ebp)
+#define FPU_accum_0	-16(%ebp)
+#define FPU_result_3	-20(%ebp)
+#define FPU_result_2	-24(%ebp)
+#define FPU_result_1	-28(%ebp)
+
+#else
+.data
+/*
+	Local storage in a static area:
+	Accumulator:	FPU_accum_3:FPU_accum_2:FPU_accum_1:FPU_accum_0
+ */
+	.align 4,0
+FPU_accum_3:
+	.long	0
+FPU_accum_2:
+	.long	0
+FPU_accum_1:
+	.long	0
+FPU_accum_0:
+	.long	0
+FPU_result_3:
+	.long	0
+FPU_result_2:
+	.long	0
+FPU_result_1:
+	.long	0
+#endif /* NON_REENTRANT_FPU */
+
+
+.text
+ENTRY(div_Xsig)
+	pushl	%ebp
+	movl	%esp,%ebp
+#ifndef NON_REENTRANT_FPU
+	subl	$28,%esp
+#endif /* NON_REENTRANT_FPU */ 
+
+	pushl	%esi
+	pushl	%edi
+	pushl	%ebx
+
+	movl	PARAM1,%esi	/* pointer to num */
+	movl	PARAM2,%ebx	/* pointer to denom */
+
+#ifdef PARANOID
+	testl	$0x80000000, XsigH(%ebx)	/* Divisor */
+	je	L_bugged
+#endif /* PARANOID */
+
+
+/*---------------------------------------------------------------------------+
+ |  Divide:   Return  arg1/arg2 to arg3.                                     |
+ |                                                                           |
+ |  The maximum returned value is (ignoring exponents)                       |
+ |               .ffffffff ffffffff                                          |
+ |               ------------------  =  1.ffffffff fffffffe                  |
+ |               .80000000 00000000                                          |
+ | and the minimum is                                                        |
+ |               .80000000 00000000                                          |
+ |               ------------------  =  .80000000 00000001   (rounded)       |
+ |               .ffffffff ffffffff                                          |
+ |                                                                           |
+ +---------------------------------------------------------------------------*/
+
+	/* Save extended dividend in local register */
+
+	/* Divide by 2 to prevent overflow */
+	clc
+	movl	XsigH(%esi),%eax
+	rcrl	%eax
+	movl	%eax,FPU_accum_3
+	movl	XsigL(%esi),%eax
+	rcrl	%eax
+	movl	%eax,FPU_accum_2
+	movl	XsigLL(%esi),%eax
+	rcrl	%eax
+	movl	%eax,FPU_accum_1
+	movl	$0,%eax
+	rcrl	%eax
+	movl	%eax,FPU_accum_0
+
+	movl	FPU_accum_2,%eax	/* Get the current num */
+	movl	FPU_accum_3,%edx
+
+/*----------------------------------------------------------------------*/
+/* Initialization done.
+   Do the first 32 bits. */
+
+	/* We will divide by a number which is too large */
+	movl	XsigH(%ebx),%ecx
+	addl	$1,%ecx
+	jnc	LFirst_div_not_1
+
+	/* here we need to divide by 100000000h,
+	   i.e., no division at all.. */
+	mov	%edx,%eax
+	jmp	LFirst_div_done
+
+LFirst_div_not_1:
+	divl	%ecx		/* Divide the numerator by the augmented
+				   denom ms dw */
+
+LFirst_div_done:
+	movl	%eax,FPU_result_3	/* Put the result in the answer */
+
+	mull	XsigH(%ebx)	/* mul by the ms dw of the denom */
+
+	subl	%eax,FPU_accum_2	/* Subtract from the num local reg */
+	sbbl	%edx,FPU_accum_3
+
+	movl	FPU_result_3,%eax	/* Get the result back */
+	mull	XsigL(%ebx)	/* now mul the ls dw of the denom */
+
+	subl	%eax,FPU_accum_1	/* Subtract from the num local reg */
+	sbbl	%edx,FPU_accum_2
+	sbbl	$0,FPU_accum_3
+	je	LDo_2nd_32_bits		/* Must check for non-zero result here */
+
+#ifdef PARANOID
+	jb	L_bugged_1
+#endif /* PARANOID */ 
+
+	/* need to subtract another once of the denom */
+	incl	FPU_result_3	/* Correct the answer */
+
+	movl	XsigL(%ebx),%eax
+	movl	XsigH(%ebx),%edx
+	subl	%eax,FPU_accum_1	/* Subtract from the num local reg */
+	sbbl	%edx,FPU_accum_2
+
+#ifdef PARANOID
+	sbbl	$0,FPU_accum_3
+	jne	L_bugged_1	/* Must check for non-zero result here */
+#endif /* PARANOID */ 
+
+/*----------------------------------------------------------------------*/
+/* Half of the main problem is done, there is just a reduced numerator
+   to handle now.
+   Work with the second 32 bits, FPU_accum_0 not used from now on */
+LDo_2nd_32_bits:
+	movl	FPU_accum_2,%edx	/* get the reduced num */
+	movl	FPU_accum_1,%eax
+
+	/* need to check for possible subsequent overflow */
+	cmpl	XsigH(%ebx),%edx
+	jb	LDo_2nd_div
+	ja	LPrevent_2nd_overflow
+
+	cmpl	XsigL(%ebx),%eax
+	jb	LDo_2nd_div
+
+LPrevent_2nd_overflow:
+/* The numerator is greater or equal, would cause overflow */
+	/* prevent overflow */
+	subl	XsigL(%ebx),%eax
+	sbbl	XsigH(%ebx),%edx
+	movl	%edx,FPU_accum_2
+	movl	%eax,FPU_accum_1
+
+	incl	FPU_result_3	/* Reflect the subtraction in the answer */
+
+#ifdef PARANOID
+	je	L_bugged_2	/* Can't bump the result to 1.0 */
+#endif /* PARANOID */ 
+
+LDo_2nd_div:
+	cmpl	$0,%ecx		/* augmented denom msw */
+	jnz	LSecond_div_not_1
+
+	/* %ecx == 0, we are dividing by 1.0 */
+	mov	%edx,%eax
+	jmp	LSecond_div_done
+
+LSecond_div_not_1:
+	divl	%ecx		/* Divide the numerator by the denom ms dw */
+
+LSecond_div_done:
+	movl	%eax,FPU_result_2	/* Put the result in the answer */
+
+	mull	XsigH(%ebx)	/* mul by the ms dw of the denom */
+
+	subl	%eax,FPU_accum_1	/* Subtract from the num local reg */
+	sbbl	%edx,FPU_accum_2
+
+#ifdef PARANOID
+	jc	L_bugged_2
+#endif /* PARANOID */
+
+	movl	FPU_result_2,%eax	/* Get the result back */
+	mull	XsigL(%ebx)	/* now mul the ls dw of the denom */
+
+	subl	%eax,FPU_accum_0	/* Subtract from the num local reg */
+	sbbl	%edx,FPU_accum_1	/* Subtract from the num local reg */
+	sbbl	$0,FPU_accum_2
+
+#ifdef PARANOID
+	jc	L_bugged_2
+#endif /* PARANOID */
+
+	jz	LDo_3rd_32_bits
+
+#ifdef PARANOID
+	cmpl	$1,FPU_accum_2
+	jne	L_bugged_2
+#endif /* PARANOID */ 
+
+	/* need to subtract another once of the denom */
+	movl	XsigL(%ebx),%eax
+	movl	XsigH(%ebx),%edx
+	subl	%eax,FPU_accum_0	/* Subtract from the num local reg */
+	sbbl	%edx,FPU_accum_1
+	sbbl	$0,FPU_accum_2
+
+#ifdef PARANOID
+	jc	L_bugged_2
+	jne	L_bugged_2
+#endif /* PARANOID */ 
+
+	addl	$1,FPU_result_2	/* Correct the answer */
+	adcl	$0,FPU_result_3
+
+#ifdef PARANOID
+	jc	L_bugged_2	/* Must check for non-zero result here */
+#endif /* PARANOID */ 
+
+/*----------------------------------------------------------------------*/
+/* The division is essentially finished here, we just need to perform
+   tidying operations.
+   Deal with the 3rd 32 bits */
+LDo_3rd_32_bits:
+	/* We use an approximation for the third 32 bits.
+	To take account of the 3rd 32 bits of the divisor
+	(call them del), we subtract  del * (a/b) */
+
+	movl	FPU_result_3,%eax	/* a/b */
+	mull	XsigLL(%ebx)		/* del */
+
+	subl	%edx,FPU_accum_1
+
+	/* A borrow indicates that the result is negative */
+	jnb	LTest_over
+
+	movl	XsigH(%ebx),%edx
+	addl	%edx,FPU_accum_1
+
+	subl	$1,FPU_result_2		/* Adjust the answer */
+	sbbl	$0,FPU_result_3
+
+	/* The above addition might not have been enough, check again. */
+	movl	FPU_accum_1,%edx	/* get the reduced num */
+	cmpl	XsigH(%ebx),%edx	/* denom */
+	jb	LDo_3rd_div
+
+	movl	XsigH(%ebx),%edx
+	addl	%edx,FPU_accum_1
+
+	subl	$1,FPU_result_2		/* Adjust the answer */
+	sbbl	$0,FPU_result_3
+	jmp	LDo_3rd_div
+
+LTest_over:
+	movl	FPU_accum_1,%edx	/* get the reduced num */
+
+	/* need to check for possible subsequent overflow */
+	cmpl	XsigH(%ebx),%edx	/* denom */
+	jb	LDo_3rd_div
+
+	/* prevent overflow */
+	subl	XsigH(%ebx),%edx
+	movl	%edx,FPU_accum_1
+
+	addl	$1,FPU_result_2	/* Reflect the subtraction in the answer */
+	adcl	$0,FPU_result_3
+
+LDo_3rd_div:
+	movl	FPU_accum_0,%eax
+	movl	FPU_accum_1,%edx
+	divl	XsigH(%ebx)
+
+	movl    %eax,FPU_result_1       /* Rough estimate of third word */
+
+	movl	PARAM3,%esi		/* pointer to answer */
+
+	movl	FPU_result_1,%eax
+	movl	%eax,XsigLL(%esi)
+	movl	FPU_result_2,%eax
+	movl	%eax,XsigL(%esi)
+	movl	FPU_result_3,%eax
+	movl	%eax,XsigH(%esi)
+
+L_exit:
+	popl	%ebx
+	popl	%edi
+	popl	%esi
+
+	leave
+	ret
+
+
+#ifdef PARANOID
+/* The logic is wrong if we got here */
+L_bugged:
+	pushl	EX_INTERNAL|0x240
+	call	EXCEPTION
+	pop	%ebx
+	jmp	L_exit
+
+L_bugged_1:
+	pushl	EX_INTERNAL|0x241
+	call	EXCEPTION
+	pop	%ebx
+	jmp	L_exit
+
+L_bugged_2:
+	pushl	EX_INTERNAL|0x242
+	call	EXCEPTION
+	pop	%ebx
+	jmp	L_exit
+#endif /* PARANOID */