x86: Don't check for BIOS corruption in first 64K when there's no need to
Due to commit 781c5a67f152c17c3e4a9ed9647f8c0be6ea5ae9 it is
likely that the number of areas to scan for BIOS corruption is 0
-- especially when the first 64K is already reserved
(X86_RESERVE_LOW is 64K by default).
If that's the case then don't set up the scan.
Signed-off-by: Naga Chumbalkar <nagananda.chumbalkar@hp.com>
Cc: <stable@kernel.org>
LKML-Reference: <20110225202838.2229.71011.sendpatchset@nchumbalkar.americas.hpqcorp.net>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
diff --git a/arch/x86/kernel/check.c b/arch/x86/kernel/check.c
index 13a3891..452932d 100644
--- a/arch/x86/kernel/check.c
+++ b/arch/x86/kernel/check.c
@@ -106,8 +106,8 @@
addr += size;
}
- printk(KERN_INFO "Scanning %d areas for low memory corruption\n",
- num_scan_areas);
+ if (num_scan_areas)
+ printk(KERN_INFO "Scanning %d areas for low memory corruption\n", num_scan_areas);
}
@@ -143,12 +143,12 @@
{
check_for_bios_corruption();
schedule_delayed_work(&bios_check_work,
- round_jiffies_relative(corruption_check_period*HZ));
+ round_jiffies_relative(corruption_check_period*HZ));
}
static int start_periodic_check_for_corruption(void)
{
- if (!memory_corruption_check || corruption_check_period == 0)
+ if (!num_scan_areas || !memory_corruption_check || corruption_check_period == 0)
return 0;
printk(KERN_INFO "Scanning for low memory corruption every %d seconds\n",