btrfs: define BTRFS_MAGIC as a u64 value
super.magic is an le64 but it's treated as an unterminated string when
compared against BTRFS_MAGIC which is defined as a string. Instead
define BTRFS_MAGIC as a normal hex value and use endian helpers to
compare it to the super's magic.
I tested this by mounting an fs made before the change and made sure
that it didn't introduce sparse errors. This matches a similar cleanup
that is pending in btrfs-progs. David Sterba pointed out that we should
fix the kernel side as well :).
Signed-off-by: Zach Brown <zab@redhat.com>
Signed-off-by: Josef Bacik <jbacik@fusionio.com>
diff --git a/fs/btrfs/check-integrity.c b/fs/btrfs/check-integrity.c
index 11d47bf..18af6f4 100644
--- a/fs/btrfs/check-integrity.c
+++ b/fs/btrfs/check-integrity.c
@@ -813,8 +813,7 @@
(bh->b_data + (dev_bytenr & 4095));
if (btrfs_super_bytenr(super_tmp) != dev_bytenr ||
- strncmp((char *)(&(super_tmp->magic)), BTRFS_MAGIC,
- sizeof(super_tmp->magic)) ||
+ super_tmp->magic != cpu_to_le64(BTRFS_MAGIC) ||
memcmp(device->uuid, super_tmp->dev_item.uuid, BTRFS_UUID_SIZE) ||
btrfs_super_nodesize(super_tmp) != state->metablock_size ||
btrfs_super_leafsize(super_tmp) != state->metablock_size ||